Re: Quick Groovy script to delete Job builds

On 03/17 14:38, Barak Korren wrote: > Hi there, > > > Working on cleaning up Jenkins I came up with the following Groovy script: > > job_name = 'ovirt-engine_3.6_build-artifacts-fc22-x86_64' > successful_to_keep = 5 > > job = Hudson.instance.getJob(job_name) > > recent_success_times = > job._getRuns(). > findAll({k, v -> v.result == Result.SUCCESS }). > collect([], { k, v -> v.time }). > sort().reverse().take(successful_to_keep) > > third_success = recent_success_times.last() > > job._getRuns(). > findAll({ k, v -> v.time < third_success }). > each({ k, v -> v.delete() }) > > The script deletes all builds older then the 5th last successful build. There's a plugin installed called 'scriptler' that allows you to put those groovy scripts there, there are already a couple iirc > > -- > Barak Korren > bkorren(a)redhat.com > RHEV-CI Team > _______________________________________________ > Infra mailing list > Infra(a)ovirt.org > http://lists.ovirt.org/mailman/listinfo/infra -- David Caro Red Hat S.L. Continuous Integration Engineer - EMEA ENG Virtualization R&D Tel.: +420 532 294 605 Email: dcaro(a)redhat.com IRC: dcaro|dcaroest@{freenode|oftc|redhat} Web: www.redhat.com RHT Global #: 82-62605 _______________________________________________ Infra mailing list Infra(a)ovirt.org http://lists.ovirt.org/mailman/listinfo/infra