You can do that using something like: snapshot_service = snapshots_service.snapshot_service(snapshot.id) snapshot = snapshot_service.get() if snapshot.snapshot_status == types.SnapshotStatus.OK: ... But counting on the snapshot status is race prone, so in 4.2 a search by correlation id was introduced and you can do something like this (taken from ovirt-system-tests[1]): correlation_id = uuid.uuid4() vm1_snapshots_service.add(dead_snap1_params, query={'correlation_id': correlation_id}) testlib.assert_true_within_long( lambda: test_utils.all_jobs_finished(engine, correlation_id) ) Where all jobs finished does: try: jobs = engine.jobs_service().list( search='correlation_id=%s' % correlation_id ) except: jobs = engine.jobs_service().list() return all(job.status != types.JobStatus.STARTED for job in jobs) [1] - https://github.com/oVirt/ovirt-system-tests/blob/master/basic-suite-master/t... On Mon, Apr 9, 2018 at 2:42 PM, <nicolas@devels.es> wrote:

Hi,

I'm running ovirt-engine-sdk-python 4.2.4 and I'm performing some snapshot-related tasks. I'd like to somehow control the status of the snapshot in order to know when I'll be able to run the next snapshot-related operation.

For example, I'd like to create a new snapshot and then delete X oldest snapshots. After creating the snapshot I have to make sure the snapshot operation has concluded to run the deletion.

However, I'm unable to find a native way to get the status of a snapshot.

In [1]: snap = conn.follow_link(vm.snapshots)[3] # This returns one snapshot

In [2]: snap.status

In [3]: snap.status_detail

So both status-related properties return None. I've managed to find a "poorman's" way by doing this:

while True: try: snaps_service.service(snap.id).remove() except Error, e: if e.code == 409: sleep(30) continue else: break

Which works but is quite "tricky".

Is there a better way to do this?

Thanks. _______________________________________________ Users mailing list Users@ovirt.org http://lists.ovirt.org/mailman/listinfo/users