Reviewed-by: Daniel Barboza <danielhb(a)linux.vnet.ibm.com>
On 11/11/2014 06:46 PM, Aline Manera wrote:
When libvirt does not support virDomain.metadata() we need to do
string
manupulation to remove the Kimchi namespace. It was done using regex
which was causing problems to remove undesirable content.
Signed-off-by: Aline Manera <alinefm(a)linux.vnet.ibm.com>
---
src/kimchi/model/utils.py | 22 ++++++++++------------
1 file changed, 10 insertions(+), 12 deletions(-)
diff --git a/src/kimchi/model/utils.py b/src/kimchi/model/utils.py
index 7dcabf8..d084f74 100644
--- a/src/kimchi/model/utils.py
+++ b/src/kimchi/model/utils.py
@@ -18,10 +18,9 @@
# Foundation, Inc., 51 Franklin Street, Fifth Floor, Boston, MA 02110-1301 USA
import libvirt
-import re
import socket
import urlparse
-from lxml import etree
+from lxml import etree, objectify
from lxml.builder import E, ElementMaker
from kimchi.exception import OperationFailed
@@ -136,17 +135,16 @@ def _kimchi_get_metadata_node(dom, tag):
root = etree.fromstring(xml)
kimchi = root.find("metadata/{%s}kimchi" % KIMCHI_META_URL)
# remove the "kimchi" prefix of xml
- # some developers may do not like to remove prefix by children iteration
- # so here, use re to remove the "kimchi" prefix of xml
- # and developers please don not define element like this:
- # <foo attr="foo<kimchi:abcd>foo"></foo>
if kimchi is not None:
- kimchi_xml = etree.tostring(kimchi)
- ns_pattern = re.compile("
xmlns:.*?=((\".*?\")|('.*?'))")
- kimchi_xml = ns_pattern.sub("", kimchi_xml)
- prefix_pattern = re.compile("(?<=<)[^/]*?:|(?<=</).*?:")
- kimchi_xml = prefix_pattern.sub("", kimchi_xml)
- return etree.fromstring(kimchi_xml)
+ for elem in kimchi.getiterator():
+ if not hasattr(elem.tag, 'find'):
+ continue
+ i = elem.tag.find('}')
+ if i >= 0:
+ elem.tag = elem.tag[i+1:]
+
+ objectify.deannotate(kimchi, cleanup_namespaces=True)
+ return kimchi
return None