Opened a bug to track it.
I tried it again today and found below:
1. I can create 2 templates with the same volume of iSCSI storage pool.
2. I can create 2 guests with the same template configured against a
volume of iSCSI storage pool.
I think both the design and implementation have problems
1. For template, as it need to be used to create multiple guests,
resources there must be collection like network/storage pool, should
not be a volume.
2. As volume need to support both read/write, we need to avoid 2
guests use the same volume as boot disk.
Recommended design:
1. In template, when edit, only list storage pool, remove iscsi pool
volumes there.
2. When create guest, once user selected the template, if it is iscsi,
add a section with a dropdown list for user to select volume, for
volume already in use, filter them out.
On 9/19/2014 10:48 AM, Aline Manera wrote:
>
> On 09/18/2014 08:07 AM, Yu Xin Huo wrote:
>> I got a iSCSI target to work on my redhat with a USB disk to test
>> iSCSI storage pool and found below:
>>
>> 1. When create a iSCSI storage pool, I selected a target in dropdown
>> list.
>> 2. Once the pool is created, I see a volume named 'unit:0:0:1'.
>> 3. When edit template, in the 'storage pool' dropdown,
'unit:0:0:1'
>> is listed there.
>>
>> So 'unit:0:0:1' which indeed is a *volume* but listed as a *pool* in
>> template? or something I am misunderstanding?
>
> The "Storage pool" on Template represents where the guest disk will
> be created.
> So if I specify "default" pool and size 10GB my guest will have a
> 10GB disk created on the default pool (under /var/lib/libvirt/images,
> for example)
>
> But it is not true for iSCSI and SCSI pools.
> We call the iSCSI and SCSI pools as read-only because we can not
> create new files on it.
> The volumes are pre-configured by the system. Because that while
> using those pools you also need to select the volume as are
> represented by <pool_name>/<vol_name> in the combo box.
>
> When a iSCSI or SCSI pool/volume is selected on Template the user can
> not edit its size, as the volume already exists and has a size.
>
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