If several users try to update the same VM at the same time, an error
may happen due to concurrent access.
Define a dictionary containing one lock per each VM, and use it when
updating the VM: the lock is acquired before the update operation begins
and it is released when the operation finishes (whether by success or
failure).
Signed-off-by: CrÃstian Deives <cristiandeives(a)gmail.com>
---
src/kimchi/model/vms.py | 18 ++++++++++++++----
1 file changed, 14 insertions(+), 4 deletions(-)
diff --git a/src/kimchi/model/vms.py b/src/kimchi/model/vms.py
index 106e9bc..e3819dc 100644
--- a/src/kimchi/model/vms.py
+++ b/src/kimchi/model/vms.py
@@ -23,6 +23,7 @@ from lxml import etree, objectify
import os
import random
import string
+import threading
import time
import uuid
from xml.etree import ElementTree
@@ -75,6 +76,9 @@ XPATH_DOMAIN_UUID = '/domain/uuid'
XPATH_NUMA_CELL = './cpu/numa/cell'
+# key: VM name; value: lock object
+vm_locks = {}
+
class VMsModel(object):
def __init__(self, **kargs):
@@ -196,10 +200,16 @@ class VMModel(object):
self.stats = {}
def update(self, name, params):
- dom = self.get_vm(name, self.conn)
- dom = self._static_vm_update(dom, params)
- self._live_vm_update(dom, params)
- return dom.name().decode('utf-8')
+ lock = vm_locks.get(name)
+ if lock is None:
+ lock = threading.Lock()
+ vm_locks[name] = lock
+
+ with lock:
+ dom = self.get_vm(name, self.conn)
+ dom = self._static_vm_update(dom, params)
+ self._live_vm_update(dom, params)
+ return dom.name().decode('utf-8')
def clone(self, name):
"""Clone a virtual machine based on an existing one.
--
2.4.3