If several users try to update the same VM at the same time, an error may happen due to concurrent access. Define a dictionary containing one lock per each VM, and use it when updating the VM: the lock is acquired before the update operation begins and it is released when the operation finishes (whether by success or failure). Signed-off-by: CrÃstian Deives <cristiandeives@gmail.com> --- src/kimchi/model/vms.py | 18 ++++++++++++++---- 1 file changed, 14 insertions(+), 4 deletions(-) diff --git a/src/kimchi/model/vms.py b/src/kimchi/model/vms.py index 106e9bc..e3819dc 100644 --- a/src/kimchi/model/vms.py +++ b/src/kimchi/model/vms.py @@ -23,6 +23,7 @@ from lxml import etree, objectify import os import random import string +import threading import time import uuid from xml.etree import ElementTree @@ -75,6 +76,9 @@ XPATH_DOMAIN_UUID = '/domain/uuid' XPATH_NUMA_CELL = './cpu/numa/cell' +# key: VM name; value: lock object +vm_locks = {} + class VMsModel(object): def __init__(self, **kargs): @@ -196,10 +200,16 @@ class VMModel(object): self.stats = {} def update(self, name, params): - dom = self.get_vm(name, self.conn) - dom = self._static_vm_update(dom, params) - self._live_vm_update(dom, params) - return dom.name().decode('utf-8') + lock = vm_locks.get(name) + if lock is None: + lock = threading.Lock() + vm_locks[name] = lock + + with lock: + dom = self.get_vm(name, self.conn) + dom = self._static_vm_update(dom, params) + self._live_vm_update(dom, params) + return dom.name().decode('utf-8') def clone(self, name): """Clone a virtual machine based on an existing one. -- 2.4.3