- When run_command does not find the command it handles the exception by logging it as an error. However that might not be an error, but the caller has no chance to work around it. Now, the exception is logged as debug and the caller is responsible to check the return code to decide what to do with such error. Signed-off-by: Jose Ricardo Ziviani <joserz(a)linux.vnet.ibm.com&gt; --- src/kimchi/utils.py | 5 +++++ 1 file changed, 5 insertions(+) diff --git a/src/kimchi/utils.py b/src/kimchi/utils.py index d71338a..ff3a5da 100644 --- a/src/kimchi/utils.py +++ b/src/kimchi/utils.py @@ -223,6 +223,11 @@ def run_command(cmd, timeout=None): return out, error, proc.returncode except TimeoutExpired: raise + except OSError as e: + msg = "Impossible to execute '%s'" % ' '.join(cmd) + kimchi_log.debug("%s", msg) + + return None, "%s %s" % (msg, e), -1 except Exception as e: msg = "Failed to run command: %s." % " ".join(cmd) msg = msg if proc is None else msg + "\n error code: %s."